If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3g^2+10g-13=0
a = 3; b = 10; c = -13;
Δ = b2-4ac
Δ = 102-4·3·(-13)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-16}{2*3}=\frac{-26}{6} =-4+1/3 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+16}{2*3}=\frac{6}{6} =1 $
| x^2+20x-36=24 | | 7n=-9+10n | | 2+7n=2-9+5n(2) | | .19+.08(y+5000)=1210 | | Y=-16x-157 | | 5^(x+3)-5^x=100 | | 2=1.11^n | | 5x^2=-36 | | 5x+800=8600 | | 3(x-1)-(x+4)=x+5(x-1) | | 3(x+1)-(x+4)=x+5(x-1) | | (1)/(16)=64^(3x+5) | | 54=6+6d | | x2−4x+29=0 | | 4x-24=3x-14= | | 4x-24+3x-14=180 | | 180=(4×+70)+(6x+60)+(2x+20) | | 2(3x+4)=5x+12 | | -5(x+2)-2=9-(x+1) | | 5x-6=7x-46 | | 6=7+2(7p+2) | | 3(m+3)^2+14(m+3)+15=0 | | 6x2-36x+48=0 | | |4x+3|+7=2 | | (X+5)^2=2x^2+2x+37 | | 400=(4a)^2 | | H=-16t^2+120t+300 | | 32=2+2d | | 32=2+5d | | 4+(4x-3)=7 | | -5x-4(1-3x)=18+7x | | 4j−10=3j−8 |